5n^2(n^2-2)=80-19n^2

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Solution for 5n^2(n^2-2)=80-19n^2 equation: 



5n^2(n^2-2)=80-19n^2

We move all terms to the left:

5n^2(n^2-2)-(80-19n^2)=0

We get rid of parentheses

5n^2(n^2-2)+19n^2-80=0

We add all the numbers together, and all the variables

19n^2+5n^2(n^2-2)-80=0

We move all terms containing n to the left, all other terms to the right

19n^2+5n^2(n^2-2)=80

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